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6n^2+46n=8
We move all terms to the left:
6n^2+46n-(8)=0
a = 6; b = 46; c = -8;
Δ = b2-4ac
Δ = 462-4·6·(-8)
Δ = 2308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2308}=\sqrt{4*577}=\sqrt{4}*\sqrt{577}=2\sqrt{577}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(46)-2\sqrt{577}}{2*6}=\frac{-46-2\sqrt{577}}{12} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(46)+2\sqrt{577}}{2*6}=\frac{-46+2\sqrt{577}}{12} $
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